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Describe and explain the effect of relative molecular mass on the rate of diffusion of gases.
Diffusion is the net movement of particles from a region of high concentration to a region of low concentration. This movement occurs because of the random motion of particles.
The rate of diffusion is influenced by several factors, including:
The rate of diffusion of a gas is inversely proportional to the square root of its relative molecular mass (Mr). This means that as the relative molecular mass of a gas increases, its diffusion rate decreases.
Explanation:
Diffusion is driven by the kinetic energy of the particles. Kinetic energy is related to mass by the equation: $$KE = \frac{1}{2}mv^2$$, where KE is kinetic energy, m is mass, and v is velocity. Since velocity is proportional to the square root of mass (v = $\sqrt{\frac{2KE}{m}}$), a heavier molecule will have a lower velocity for the same kinetic energy. Therefore, lighter molecules move faster and diffuse more quickly.
The relationship between the rate of diffusion (r) and the relative molecular mass (Mr) can be expressed as:
$$r \propto \frac{1}{\sqrt{Mr}}$$This can also be written as:
$$r = \frac{k}{\sqrt{Mr}}$$where k is a constant of proportionality.
Consider the diffusion of nitrogen (N2), oxygen (O2), and carbon dioxide (CO2) at the same temperature and pressure.
N2 has an Mr of 28 g/mol, O2 has an Mr of 32 g/mol, and CO2 has an Mr of 44 g/mol.
Therefore, the rate of diffusion will be:
Gas | Relative Molecular Mass (Mr) | Relative Diffusion Rate |
---|---|---|
Carbon Dioxide (CO2) | 44 | Lowest |
Oxygen (O2) | 32 | Intermediate |
Nitrogen (N2) | 28 | Highest |
Experiments involving the diffusion of gases through porous barriers have demonstrated the effect of relative molecular mass on diffusion rate. The rate of diffusion is faster for gases with lower molecular masses.