Resources | Subject Notes | Physics
This section explores the relationship between a magnetic field and an electric current, leading to the concept of a force acting on a current-carrying conductor placed within a magnetic field. We will recall and apply the right-hand rule to determine the direction of this force.
The magnitude of the force (F) on a current-carrying conductor in a magnetic field is given by the equation:
$$F = I L B \sin \theta$$
Where:
The right-hand rule is used to determine the direction of the force. There are a few variations, but the most common one is:
If the current and magnetic field are perpendicular (θ = 90°), the force is at its maximum value: $$F = I L B$$
A current of 2 A flows through a straight wire of length 0.5 m placed in a magnetic field of 0.4 T. The current is perpendicular to the magnetic field. Calculate the force on the wire.
Using the formula: $$F = I L B$$
$$F = 2 \text{ A} \times 0.5 \text{ m} \times 0.4 \text{ T} = 0.4 \text{ N}$$
The direction of the force can be determined using the right-hand rule. The force will be perpendicular to both the wire (current direction) and the magnetic field.
Quantity | Symbol | Units |
---|---|---|
Force on a current-carrying conductor | F | Newtons (N) |
Current | I | Amperes (A) |
Length of conductor in magnetic field | L | Meters (m) |
Magnetic field strength | B | Teslas (T) |
Angle between current and magnetic field | θ | Degrees (° or radians) |
Understanding the force on a current-carrying conductor is fundamental to many electrical and magnetic applications, including electric motors and actuators.