Resources | Subject Notes | Mathematics
This section covers the analysis of forces acting on objects, including motion on rough surfaces, systems of connected particles, and the conditions for equilibrium of rigid bodies. We will explore concepts such as friction, tension, and the application of Newton's laws to these scenarios.
When an object moves on a rough surface, it experiences several forces: gravity, the normal force, and the frictional force. The frictional force opposes the motion.
Static friction is the force that prevents an object from starting to move. It can vary in magnitude up to a maximum value.
The maximum static friction force ($f_{s,max}$) is given by:
$$f_{s,max} = \mu_s N$$ where:An object will remain at rest or move with constant velocity as long as the applied force is less than or equal to the maximum static friction force.
Kinetic friction is the force that opposes the motion of an object already in motion. It is generally less than static friction.
The kinetic friction force ($f_k$) is given by:
$$f_k = \mu_k N$$ where:Consider an object of mass $m$ on a horizontal surface with coefficient of static friction $\mu_s$ and coefficient of kinetic friction $\mu_k$. The normal force is equal to the weight of the object ($N = mg$).
If an external horizontal force $F$ is applied:
When particles are connected by strings or rods, the forces acting on each particle must be considered. We often use diagrams to represent these situations.
Consider two particles of mass $m$ connected by a light, inextensible string of mass $m$. The system is placed on a frictionless table and a horizontal force $F$ is applied to one of the particles.
The forces acting on the system are:
Applying Newton's second law to the system:
$$m \frac{d^2x}{dt^2} = F - 2T$$ where $x$ is the displacement of the particles from their initial positions.A rigid body is in equilibrium if the net force acting on it is zero and the net torque about any point is also zero.
For a rigid body to be in equilibrium, the following conditions must be met:
Consider a rigid body in equilibrium. We can choose any point on the body as the reference point for calculating torques. The torque $\tau$ is given by:
$$\tau = r \times F \sin \theta$$ where $r$ is the position vector from the reference point to the point where the force is applied, $F$ is the force vector, and $\theta$ is the angle between $r$ and $F$.For equilibrium, the sum of all torques about the chosen point must be zero.
Topic | Key Concepts |
---|---|
Forces on a Rough Surface | Static friction, kinetic friction, coefficient of static friction ($\mu_s$), coefficient of kinetic friction ($\mu_k$), normal force ($N$), maximum static friction force ($f_{s,max}$). |
Connected Particles | Tension, Newton's second law, system analysis. |
Equilibrium of Rigid Bodies | Net force = 0, Net torque = 0, Torque calculation ($τ = r \times F \sin \theta$). |