The Benedict's test relies on the principle of redox (reduction-oxidation) chemistry. Reducing sugars are carbohydrates that can donate electrons. The test exploits this property using copper(II) ions (Cu2+) in an alkaline solution.
Redox Reaction: In the alkaline solution, the reducing sugar is oxidized (loses electrons) and the copper(II) ions are reduced (gain electrons). The specific reaction is as follows:
Cu2+ (aq) + Reducing Sugar (e.g., Aldose) → Cu+ (aq) + Oxidized Sugar + H+
Role of Alkaline Solution: The alkaline (basic) solution is crucial for the reaction to proceed. The hydroxide ions (OH-) from the alkaline solution facilitate the reduction of copper(II) ions. They provide a suitable environment for the transfer of electrons and stabilize the copper(I) ion formed during the reduction process. Without the alkaline conditions, the reaction would not occur efficiently.
Significance of Colour Change: The colour change from blue to green, orange, and finally brick red is directly related to the change in the oxidation state of copper.
- Blue (No colour change): Indicates the absence of reducing sugars. The copper(II) ions remain in their original state.
- Green (Low concentration): A small amount of reducing sugar is present, leading to a partial reduction of copper(II) to copper(I).
- Orange (Moderate concentration): A moderate amount of reducing sugar is present, resulting in a more significant reduction of copper(II) to copper(I).
- Brick Red (High concentration): A high concentration of reducing sugar is present, leading to a complete reduction of copper(II) to copper(I). The copper(I) ions form a reddish-brown precipitate of cuprous oxide (Cu2O), which gives the brick-red colour.
Therefore, the intensity of the colour change provides a visual indication of the concentration of reducing sugars in the sample. The more reducing sugar present, the more copper(II) is reduced, and the deeper the colour becomes.