Resources | Subject Notes | Physics
A potential divider is a simple circuit used to reduce a voltage to a lower level. It consists of two resistors connected in series. The voltage is divided between these resistors in proportion to their resistances.
The voltage across each resistor in a potential divider can be calculated using the following equation:
$V_1 = \frac{R_1}{R_1 + R_2} \times V_{total}$
$V_2 = \frac{R_2}{R_1 + R_2} \times V_{total}$
Where:
When a voltage ($V_{total}$) is applied across the series combination of two resistors ($R_1$ and $R_2$), the current ($I$) flowing through both resistors is the same. The voltage drop across each resistor is proportional to its resistance. A larger resistance will experience a larger voltage drop.
Consider a potential divider with $R_1 = 1000 \Omega$ and $R_2 = 2000 \Omega$ connected to a $12V$ supply.
$V_1 = \frac{R_1}{R_1 + R_2} \times V_{total} = \frac{1000}{1000 + 2000} \times 12 = \frac{1000}{3000} \times 12 = 0.333 \times 12 = 4V$
$V_2 = \frac{R_2}{R_1 + R_2} \times V_{total} = \frac{2000}{1000 + 2000} \times 12 = \frac{2000}{3000} \times 12 = 0.667 \times 12 = 8V$
As you can see, $V_1 + V_2 = 4V + 8V = 12V$, which is the total applied voltage.
Potential dividers are used in a variety of applications, including:
Component | Symbol | Equation |
---|---|---|
Resistor 1 | $R_1$ | $V_1 = \frac{R_1}{R_1 + R_2} \times V_{total}$ |
Resistor 2 | $R_2$ | $V_2 = \frac{R_2}{R_1 + R_2} \times V_{total}$ |