Organic chemistry - Naming organic compounds (3)
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1.
Determine the type of compound represented by the following molecular formulas:
- a) CH4
- b) C2H4
- c) C2H5OH
- d) CH3COOH
a) CH4: Alkane - The presence of only carbon and hydrogen atoms with single bonds indicates an alkane.
b) C2H4: Alkene - The ratio of carbon and hydrogen suggests a double bond between carbon atoms, hence an alkene.
c) C2H5OH: Alcohol - The presence of a hydroxyl (-OH) group attached to a carbon atom indicates an alcohol.
d) CH3COOH: Carboxylic acid - The presence of a carboxyl (-COOH) group indicates a carboxylic acid.
2.
Question 2
Draw the structural formulae and write the displayed formulae for the following carboxylic acids:
- (a) Ethanoic acid
- (b) Propanoic acid
- (c) Butanoic acid
- (d) Pentanoic acid
Answer 2
(a) Ethanoic acid:
Structure: CH3COOH, Displayed: CH3COOH
(b) Propanoic acid:
Structure: CH3CH2COOH, Displayed: CH3CH2COOH
(c) Butanoic acid:
Structure: CH3CH2CH2COOH, Displayed: CH3CH2CH2COOH
(d) Pentanoic acid:
Structure: CH3CH2CH2CH2COOH, Displayed: CH3CH2CH2CH2COOH
3.
Describe the reaction between a carboxylic acid and an alcohol to form an ester. Include the reactants, products, and the role of an acid catalyst. Write a balanced chemical equation for the reaction.
The reaction between a carboxylic acid and an alcohol to form an ester is a condensation reaction. It involves the reaction of a carboxylic acid (RCOOH) with an alcohol (R'OH) to produce an ester (RCOOR') and water (H2O). An acid catalyst, typically sulfuric acid (H2SO4) or hydrochloric acid (HCl), is used to speed up the reaction. The acid catalyst protonates the carbonyl oxygen of the carboxylic acid, making it more susceptible to nucleophilic attack by the alcohol.
Reactants: Carboxylic acid (RCOOH) and Alcohol (R'OH)
Products: Ester (RCOOR') and Water (H2O)
Role of Acid Catalyst: The acid catalyst protonates the carbonyl oxygen of the carboxylic acid, increasing the electrophilicity of the carbonyl carbon and facilitating the nucleophilic attack by the alcohol. This lowers the activation energy of the reaction, allowing it to proceed at a faster rate.
Balanced Chemical Equation:
Equation |
RCOOH(aq) + R'OH(aq) ⇌ RCOOR'(aq) + H2O(l) |